WebThe simple pendulum system has a single particle with position vector r = (x,y,z). /Name/F6 820.5 796.1 695.6 816.7 847.5 605.6 544.6 625.8 612.8 987.8 713.3 668.3 724.7 666.7 The equation of frequency of the simple pendulum : f = frequency, g = acceleration due to gravity, l = the length of cord. /BaseFont/WLBOPZ+CMSY10 Both are suspended from small wires secured to the ceiling of a room. Ap Physics PdfAn FPO/APO address is an official address used to 295.1 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 295.1 'z.msV=eS!6\f=QE|>9lqqQ/h%80 t v{"m4T>8|m@pqXAep'|@Dq;q>mr)G?P-| +*"!b|b"YI!kZfIZNh!|!Dwug5c #6h>qp:9j(s%s*}BWuz(g}} ]7N.k=l 537|?IsV That means length does affect period. [13.9 m/s2] 2. << endobj /Type/Font /LastChar 196 675.9 1067.1 879.6 844.9 768.5 844.9 839.1 625 782.4 864.6 849.5 1162 849.5 849.5 Arc Length And Sector Area Choice Board Answer Key An engineer builds two simple pendula. 935.2 351.8 611.1] This is the video that cover the section 7. 33 0 obj Resonance of sound wave problems and solutions, Simple harmonic motion problems and solutions, Electric current electric charge magnetic field magnetic force, Quantities of physics in the linear motion. /Name/F6 593.8 500 562.5 1125 562.5 562.5 562.5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 pendulum Simple Harmonic Motion What is the acceleration of gravity at that location? Get There. This is a test of precision.). solution 525 768.9 627.2 896.7 743.3 766.7 678.3 766.7 729.4 562.2 715.6 743.3 743.3 998.9 Set up a graph of period squared vs. length and fit the data to a straight line. The linear displacement from equilibrium is, https://openstax.org/books/college-physics-2e/pages/1-introduction-to-science-and-the-realm-of-physics-physical-quantities-and-units, https://openstax.org/books/college-physics-2e/pages/16-4-the-simple-pendulum, Creative Commons Attribution 4.0 International License. /FirstChar 33 xYK WL+z^d7 =sPd3 X`H^Ea+y}WIeoY=]}~H,x0aQ@z0UX&ks0. Solution endobj Look at the equation again. Ze}jUcie[. /FirstChar 33 Length and gravity are given. These NCERT Solutions provide you with the answers to the question from the textbook, important questions from previous year question papers and sample papers. /FontDescriptor 26 0 R 27 0 obj Adding pennies to the Great Clock shortens the effective length of its pendulum by about half the width of a human hair. /FontDescriptor 32 0 R /Length 2736 What would be the period of a 0.75 m long pendulum on the Moon (g = 1.62 m/s2)? /FontDescriptor 8 0 R In part a ii we assumed the pendulum would be used in a working clock one designed to match the cultural definitions of a second, minute, hour, and day. Page Created: 7/11/2021. if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physexams_com-large-mobile-banner-2','ezslot_8',133,'0','0'])};__ez_fad_position('div-gpt-ad-physexams_com-large-mobile-banner-2-0'); Problem (10): A clock works with the mechanism of a pendulum accurately. << Let us define the potential energy as being zero when the pendulum is at the bottom of the swing, = 0 . The period of a simple pendulum with large angle is presented; a comparison has been carried out between the analytical solution and the numerical integration results. /FirstChar 33 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 753.7 1000 935.2 831.5 /FontDescriptor 23 0 R 874 706.4 1027.8 843.3 877 767.9 877 829.4 631 815.5 843.3 843.3 1150.8 843.3 843.3 Since gravity varies with location, however, this standard could only be set by building a pendulum at a location where gravity was exactly equal to the standard value something that is effectively impossible. stream /FirstChar 33 >> endobj This method isn't graphical, but I'm going to display the results on a graph just to be consistent. WebClass 11 Physics NCERT Solutions for Chapter 14 Oscillations. l(&+k:H uxu {fH@H1X("Esg/)uLsU. 877 0 0 815.5 677.6 646.8 646.8 970.2 970.2 323.4 354.2 569.4 569.4 569.4 569.4 569.4 /Type/Font 877 0 0 815.5 677.6 646.8 646.8 970.2 970.2 323.4 354.2 569.4 569.4 569.4 569.4 569.4 833.3 1444.4 1277.8 555.6 1111.1 1111.1 1111.1 1111.1 1111.1 944.4 1277.8 555.6 1000 >> If displacement from equilibrium is very small, then the pendulum of length $\ell$ approximate simple harmonic motion. A "seconds pendulum" has a half period of one second. 600.2 600.2 507.9 569.4 1138.9 569.4 569.4 569.4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 % /FirstChar 33 It consists of a point mass m suspended by means of light inextensible string of length L from a fixed support as shown in Fig. Period is the goal. Physics 6010, Fall 2010 Some examples. Constraints and <> /FontDescriptor 17 0 R not harmonic or non-sinusoidal) response of a simple pendulum undergoing moderate- to large-amplitude oscillations. There are two constraints: it can oscillate in the (x,y) plane, and it is always at a xed distance from the suspension point. The mass does not impact the frequency of the simple pendulum. 820.5 796.1 695.6 816.7 847.5 605.6 544.6 625.8 612.8 987.8 713.3 668.3 724.7 666.7 /BaseFont/CNOXNS+CMR10 The period of a pendulum on Earth is 1 minute. endobj The most popular choice for the measure of central tendency is probably the mean (gbar). /LastChar 196 I think it's 9.802m/s2, but that's not what the problem is about. The pendula are only affected by the period (which is related to the pendulums length) and by the acceleration due to gravity. >> g The SI unit for frequency is the hertz (Hz) and is defined as one cycle per second: 1 Hz = 1 cycle s or 1 Hz = 1 s = 1 s 1. 874 706.4 1027.8 843.3 877 767.9 877 829.4 631 815.5 843.3 843.3 1150.8 843.3 843.3 For the precision of the approximation Solution: The period of a simple pendulum is related to its length $\ell$ by the following formula \[T=2\pi\sqrt{\frac{\ell}{g}}\] Here, we wish $T_2=3T_1$, after some manipulations we get \begin{align*} T_2&=3T_1\\\\ 2\pi\sqrt{\frac{\ell_2}{g}} &=3\times 2\pi\sqrt{\frac{\ell_1}{g}}\\\\ \sqrt{\ell_2}&=3\sqrt{\ell_1}\\\\\Rightarrow \ell_2&=9\ell_1 \end{align*} In the last equality, we squared both sides. 28. 525 768.9 627.2 896.7 743.3 766.7 678.3 766.7 729.4 562.2 715.6 743.3 743.3 998.9 At one end of the rope suspended a mass of 10 gram and length of rope is 1 meter. 511.1 511.1 511.1 831.3 460 536.7 715.6 715.6 511.1 882.8 985 766.7 255.6 511.1] WebThe essence of solving nonlinear problems and the differences and relations of linear and nonlinear problems are also simply discussed. Pendulum . endobj /Subtype/Type1 How long is the pendulum? 6 stars and was available to sell back to BooksRun online for the top buyback price of $ 0. 42 0 obj /BaseFont/AQLCPT+CMEX10 The period of the Great Clock's pendulum is probably 4seconds instead of the crazy decimal number we just calculated. 542.4 542.4 456.8 513.9 1027.8 513.9 513.9 513.9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 % Modelling of The Simple Pendulum and It Is Numerical Solution WebIn the case of the simple pendulum or ideal spring, the force does not depend on angular velocity; but on the angular frequency. The length of the second pendulum is 0.4 times the length of the first pendulum, and the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum. << 826.4 295.1 531.3] MATHEMATICA TUTORIAL, Part 1.4: Solution of pendulum equation Physics 1 Lab Manual1Objectives: The main objective of this lab 1277.8 811.1 811.1 875 875 666.7 666.7 666.7 666.7 666.7 666.7 888.9 888.9 888.9 Problem (7): There are two pendulums with the following specifications. We can discern one half the smallest division so DVVV= ()05 01 005.. .= VV V= D ()385 005.. 4. A simple pendulum shows periodic motion, and it occurs in the vertical plane and is mainly driven by the gravitational force. Solution: The length $\ell$ and frequency $f$ of a simple pendulum are given and $g$ is unknown. 762.8 642 790.6 759.3 613.2 584.4 682.8 583.3 944.4 828.5 580.6 682.6 388.9 388.9 t@F4E80%A=%A-A{>^ii{W,.Oa[G|=YGu[_>@EB Ld0eOa{lX-Xy.R^K'0c|H|fUV@+Xo^f:?Pwmnz2i] \q3`NJUdH]e'\KD-j/\}=70@'xRsvL+4r;tu3mc|}wCy;& v5v&zXPbpp 4 0 obj Thus, The frequency of this pendulum is \[f=\frac{1}{T}=\frac{1}{3}\,{\rm Hz}\], Problem (3): Find the length of a pendulum that has a frequency of 0.5 Hz. 600.2 600.2 507.9 569.4 1138.9 569.4 569.4 569.4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 The quantities below that do not impact the period of the simple pendulum are.. B. length of cord and acceleration due to gravity. Will it gain or lose time during this movement? 481.5 675.9 643.5 870.4 643.5 643.5 546.3 611.1 1222.2 611.1 611.1 611.1 0 0 0 0 WebMass Pendulum Dynamic System chp3 15 A simple plane pendulum of mass m 0 and length l is suspended from a cart of mass m as sketched in the figure. endobj 0.5 /FontDescriptor 20 0 R Problems 473.8 498.5 419.8 524.7 1049.4 524.7 524.7 524.7 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 >> >> /FirstChar 33 444.4 611.1 777.8 777.8 777.8 777.8 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 When we discuss damping in Section 1.2, we will nd that the motion is somewhat sinusoidal, but with an important modication. @ @y ss~P_4qu+a" ' 9y c&Ls34f?q3[G)> `zQGOxis4t&0tC: pO+UP=ebLYl*'zte[m04743C 3d@C8"P)Dp|Y are licensed under a, Introduction: The Nature of Science and Physics, Introduction to Science and the Realm of Physics, Physical Quantities, and Units, Accuracy, Precision, and Significant Figures, Introduction to One-Dimensional Kinematics, Motion Equations for Constant Acceleration in One Dimension, Problem-Solving Basics for One-Dimensional Kinematics, Graphical Analysis of One-Dimensional Motion, Introduction to Two-Dimensional Kinematics, Kinematics in Two Dimensions: An Introduction, Vector Addition and Subtraction: Graphical Methods, Vector Addition and Subtraction: Analytical Methods, Dynamics: Force and Newton's Laws of Motion, Introduction to Dynamics: Newtons Laws of Motion, Newtons Second Law of Motion: Concept of a System, Newtons Third Law of Motion: Symmetry in Forces, Normal, Tension, and Other Examples of Forces, Further Applications of Newtons Laws of Motion, Extended Topic: The Four Basic ForcesAn Introduction, Further Applications of Newton's Laws: Friction, Drag, and Elasticity, Introduction: Further Applications of Newtons Laws, Introduction to Uniform Circular Motion and Gravitation, Fictitious Forces and Non-inertial Frames: The Coriolis Force, Satellites and Keplers Laws: An Argument for Simplicity, Introduction to Work, Energy, and Energy Resources, Kinetic Energy and the Work-Energy Theorem, Introduction to Linear Momentum and Collisions, Collisions of Point Masses in Two Dimensions, Applications of Statics, Including Problem-Solving Strategies, Introduction to Rotational Motion and Angular Momentum, Dynamics of Rotational Motion: Rotational Inertia, Rotational Kinetic Energy: Work and Energy Revisited, Collisions of Extended Bodies in Two Dimensions, Gyroscopic Effects: Vector Aspects of Angular Momentum, Variation of Pressure with Depth in a Fluid, Gauge Pressure, Absolute Pressure, and Pressure Measurement, Cohesion and Adhesion in Liquids: Surface Tension and Capillary Action, Fluid Dynamics and Its Biological and Medical Applications, Introduction to Fluid Dynamics and Its Biological and Medical Applications, The Most General Applications of Bernoullis Equation, Viscosity and Laminar Flow; Poiseuilles Law, Molecular Transport Phenomena: Diffusion, Osmosis, and Related Processes, Temperature, Kinetic Theory, and the Gas Laws, Introduction to Temperature, Kinetic Theory, and the Gas Laws, Kinetic Theory: Atomic and Molecular Explanation of Pressure and Temperature, Introduction to Heat and Heat Transfer Methods, The First Law of Thermodynamics and Some Simple Processes, Introduction to the Second Law of Thermodynamics: Heat Engines and Their Efficiency, Carnots Perfect Heat Engine: The Second Law of Thermodynamics Restated, Applications of Thermodynamics: Heat Pumps and Refrigerators, Entropy and the Second Law of Thermodynamics: Disorder and the Unavailability of Energy, Statistical Interpretation of Entropy and the Second Law of Thermodynamics: The Underlying Explanation, Introduction to Oscillatory Motion and Waves, Hookes Law: Stress and Strain Revisited, Simple Harmonic Motion: A Special Periodic Motion, Energy and the Simple Harmonic Oscillator, Uniform Circular Motion and Simple Harmonic Motion, Speed of Sound, Frequency, and Wavelength, Sound Interference and Resonance: Standing Waves in Air Columns, Introduction to Electric Charge and Electric Field, Static Electricity and Charge: Conservation of Charge, Electric Field: Concept of a Field Revisited, Conductors and Electric Fields in Static Equilibrium, Introduction to Electric Potential and Electric Energy, Electric Potential Energy: Potential Difference, Electric Potential in a Uniform Electric Field, Electrical Potential Due to a Point Charge, Electric Current, Resistance, and Ohm's Law, Introduction to Electric Current, Resistance, and Ohm's Law, Ohms Law: Resistance and Simple Circuits, Alternating Current versus Direct Current, Introduction to Circuits and DC Instruments, DC Circuits Containing Resistors and Capacitors, Magnetic Field Strength: Force on a Moving Charge in a Magnetic Field, Force on a Moving Charge in a Magnetic Field: Examples and Applications, Magnetic Force on a Current-Carrying Conductor, Torque on a Current Loop: Motors and Meters, Magnetic Fields Produced by Currents: Amperes Law, Magnetic Force between Two Parallel Conductors, Electromagnetic Induction, AC Circuits, and Electrical Technologies, Introduction to Electromagnetic Induction, AC Circuits and Electrical Technologies, Faradays Law of Induction: Lenzs Law, Maxwells Equations: Electromagnetic Waves Predicted and Observed, Introduction to Vision and Optical Instruments, Limits of Resolution: The Rayleigh Criterion, *Extended Topic* Microscopy Enhanced by the Wave Characteristics of Light, Photon Energies and the Electromagnetic Spectrum, Probability: The Heisenberg Uncertainty Principle, Discovery of the Parts of the Atom: Electrons and Nuclei, Applications of Atomic Excitations and De-Excitations, The Wave Nature of Matter Causes Quantization, Patterns in Spectra Reveal More Quantization, Introduction to Radioactivity and Nuclear Physics, Introduction to Applications of Nuclear Physics, The Yukawa Particle and the Heisenberg Uncertainty Principle Revisited, Particles, Patterns, and Conservation Laws, A simple pendulum has a small-diameter bob and a string that has a very small mass but is strong enough not to stretch appreciably. /LastChar 196 There are two constraints: it can oscillate in the (x,y) plane, and it is always at a xed distance from the suspension point. /Widths[622.5 466.3 591.4 828.1 517 362.8 654.2 1000 1000 1000 1000 277.8 277.8 500 A simple pendulum is defined to have an object that has a small mass, also known as the pendulum bob, which is suspended from a light wire or string, such as shown in Figure 16.13. The short way F WebMISN-0-201 7 Table1.Usefulwaverelationsandvariousone-dimensional harmonicwavefunctions.Rememberthatcosinefunctions mayalsobeusedasharmonicwavefunctions. Free vibrations ; Damped vibrations ; Forced vibrations ; Resonance ; Nonlinear models ; Driven models ; Pendulum . <> stream Some simple nonlinear problems in mechanics, for instance, the falling of a ball in fluid, the motion of a simple pendulum, 2D nonlinear water waves and so on, are used to introduce and examine the both methods. endobj 295.1 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 531.3 295.1 295.1 314.8 472.2 262.3 839.5 577.2 524.7 524.7 472.2 432.9 419.8 341.1 550.9 472.2 682.1 /FirstChar 33 500 555.6 527.8 391.7 394.4 388.9 555.6 527.8 722.2 527.8 527.8 444.4 500 1000 500 Simple pendulum ; Solution of pendulum equation ; Period of pendulum ; Real pendulum ; Driven pendulum ; Rocking pendulum ; Pumping swing ; Dyer model ; Electric circuits; endobj The displacement ss is directly proportional to . /LastChar 196 Pendulum 1 has a bob with a mass of 10kg10kg. PENDULUM WORKSHEET 1. - New Providence 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 663.6 885.4 826.4 736.8 Some have crucial uses, such as in clocks; some are for fun, such as a childs swing; and some are just there, such as the sinker on a fishing line. 306.7 766.7 511.1 511.1 766.7 743.3 703.9 715.6 755 678.3 652.8 773.6 743.3 385.6 if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physexams_com-large-mobile-banner-1','ezslot_6',148,'0','0'])};__ez_fad_position('div-gpt-ad-physexams_com-large-mobile-banner-1-0'); The period of a pendulum is defined as the time interval, in which the pendulum completes one cycle of motion and is measured in seconds. 460 664.4 463.9 485.6 408.9 511.1 1022.2 511.1 511.1 511.1 0 0 0 0 0 0 0 0 0 0 0 The masses are m1 and m2. (arrows pointing away from the point). Lagranges Equation - California State University, Northridge Half of this is what determines the amount of time lost when this pendulum is used as a time keeping device in its new location. /Font <>>> 1999-2023, Rice University. /Name/F5 /LastChar 196 This PDF provides a full solution to the problem. PHET energy forms and changes simulation worksheet to accompany simulation. /Type/Font /Type/Font SOLUTION: The length of the arc is 22 (6 + 6) = 10. 295.1 826.4 501.7 501.7 826.4 795.8 752.1 767.4 811.1 722.6 693.1 833.5 795.8 382.6 24/7 Live Expert. 805.5 896.3 870.4 935.2 870.4 935.2 0 0 870.4 736.1 703.7 703.7 1055.5 1055.5 351.8 in your own locale. /Filter[/FlateDecode] For the simple pendulum: for the period of a simple pendulum. Problem (9): Of simple pendulum can be used to measure gravitational acceleration. 935.2 351.8 611.1] Examples of Projectile Motion 1. How about some rhetorical questions to finish things off? Problem (8): A pendulum has a period of $1.7\,{\rm s}$ on Earth. 1 0 obj When the pendulum is elsewhere, its vertical displacement from the = 0 point is h = L - L cos() (see diagram) Consider the following example. /LastChar 196 This result is interesting because of its simplicity. 30 0 obj /Name/F12 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 643.8 839.5 787 710.5 682.1 763 734.6 787 734.6 777.8 777.8 1000 500 500 777.8 777.8 777.8 777.8 777.8 777.8 777.8 777.8 777.8 777.8 sin 562.5 562.5 562.5 562.5 562.5 562.5 562.5 562.5 562.5 562.5 562.5 312.5 312.5 342.6 << Perform a propagation of error calculation on the two variables: length () and period (T). Compare it to the equation for a generic power curve. Simple Pendulum Problems and Formula for High Schools << 1000 1000 1055.6 1055.6 1055.6 777.8 666.7 666.7 450 450 450 450 777.8 777.8 0 0 WebSOLUTION: Scale reads VV= 385. <> stream i.e. 3 0 obj Web3 Phase Systems Tutorial No 1 Solutions v1 PDF Lecture notes, lecture negligence Summary Small Business And Entrepreneurship Complete - Course Lead: Tom Coogan Advantages and disadvantages of entry modes 2 Lecture notes, lectures 1-19 - materials slides Frustration - Contract law: Notes with case law /LastChar 196 A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass (Figure 15.5.1 ). 639.7 565.6 517.7 444.4 405.9 437.5 496.5 469.4 353.9 576.2 583.3 602.5 494 437.5 27 0 obj Tell me where you see mass. The Island Worksheet Answers from forms of energy worksheet answers , image source: www. Math Assignments Frequency of a pendulum calculator Formula : T = 2 L g . 314.8 524.7 524.7 524.7 524.7 524.7 524.7 524.7 524.7 524.7 524.7 524.7 314.8 314.8 Creative Commons Attribution License 500 500 611.1 500 277.8 833.3 750 833.3 416.7 666.7 666.7 777.8 777.8 444.4 444.4 The period of a simple pendulum is described by this equation. Want to cite, share, or modify this book? endobj /Subtype/Type1 /Subtype/Type1 <> Substitute known values into the new equation: If you are redistributing all or part of this book in a print format, Earth, Atmospheric, and Planetary Physics /Name/F10 Problem (1): In a simple pendulum, how much the length of it must be changed to triple its period? Attach a small object of high density to the end of the string (for example, a metal nut or a car key). Get answer out. Physics 1 First Semester Review Sheet, Page 2. . Then, we displace it from its equilibrium as small as possible and release it. are not subject to the Creative Commons license and may not be reproduced without the prior and express written if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[336,280],'physexams_com-leader-1','ezslot_11',112,'0','0'])};__ez_fad_position('div-gpt-ad-physexams_com-leader-1-0'); Therefore, with increasing the altitude, $g$ becomes smaller and consequently the period of the pendulum becomes larger. The length of the cord of the simple pendulum (l) = 1 meter, Wanted: determine the length of rope if the frequency is twice the initial frequency. 351.8 935.2 578.7 578.7 935.2 896.3 850.9 870.4 915.7 818.5 786.1 941.7 896.3 442.6 /BaseFont/SNEJKL+CMBX12 UNCERTAINTY: PROBLEMS & ANSWERS pendulum /Name/F8 Websector-area-and-arc-length-answer-key 1/6 Downloaded from accreditation. A 2.2 m long simple pendulum oscillates with a period of 4.8 s on the surface of The length of the second pendulum is 0.4 times the length of the first pendulum, and the, second pendulum is 0.9 times the acceleration of gravity, The length of the cord of the first pendulum, The length of cord of the second pendulum, Acceleration due to the gravity of the first pendulum, Acceleration due to gravity of the second pendulum, he comparison of the frequency of the first pendulum (f. Hertz. WebFor periodic motion, frequency is the number of oscillations per unit time. A pendulum is a massive bob attached to a string or cord and swings back and forth in a periodic motion. /BaseFont/NLTARL+CMTI10 \(&SEc Note how close this is to one meter. A simple pendulum of length 1 m has a mass of 10 g and oscillates freely with an amplitude of 2 cm. (Keep every digit your calculator gives you. 611.1 798.5 656.8 526.5 771.4 527.8 718.7 594.9 844.5 544.5 677.8 762 689.7 1200.9 /Widths[622.5 466.3 591.4 828.1 517 362.8 654.2 1000 1000 1000 1000 277.8 277.8 500 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 458.3 458.3 416.7 416.7 Find the period and oscillation of this setup. Simple Pendulum %PDF-1.5 <> /Subtype/Type1 endobj /Type/Font Solution: In 60 seconds it makes 40 oscillations In 1 sec it makes = 40/60 = 2/3 oscillation So frequency = 2/3 per second = 0.67 Hz Time period = 1/frequency = 3/2 = 1.5 seconds 64) The time period of a simple pendulum is 2 s. /BaseFont/AVTVRU+CMBX12 Now for a mathematically difficult question. In Figure 3.3 we draw the nal phase line by itself. - Unit 1 Assignments & Answers Handout. /W [0 [777.832 0 0 250 0 408.2031 500 0 0 777.832 180.1758 333.0078 333.0078 0 563.9648 250 333.0078 250 277.832] 19 28 500 29 [277.832] 30 33 563.9648 34 [443.8477 920.8984 722.168 666.9922 666.9922 722.168 610.8398 556.1523 0 722.168 333.0078 389.1602 722.168 610.8398 889.1602 722.168 722.168 556.1523 722.168 0 556.1523 610.8398 722.168 722.168 943.8477 0 0 610.8398] 62 67 333.0078 68 [443.8477 500 443.8477 500 443.8477 333.0078 500 500 277.832 277.832 500 277.832 777.832] 81 84 500 85 [333.0078 389.1602 277.832 500 500 722.168 500 500 443.8477] 94 130 479.9805 131 [399.9023] 147 [548.8281] 171 [1000] 237 238 563.9648 242 [750] 520 [582.0313] 537 [479.0039] 550 [658.2031] 652 [504.8828] 2213 [526.3672]]>>

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